Actually I made a big mistake. It actually goes: 1) Record, 2) H2H record, 3) Division Record, 4) Record vs. Common Opponents, 5) Conference record. I forgot that common opponents goes ahead on conference record in divisional ties. An easy way to figure that out is to look at the records of the 2 teams that are not common to each team. Bears: W - @Carolina L - Seattle Packers: L - @Atlanta TBD - San Francisco So in a way, a win against SF is not a bad thing for the common opponents tiebreaker, as it means the Bears would tie the Packers in record vs. common opponents. Imagine this crazy scenario: Bears: @ Det - W NE - L @ Min - W NYJ - W @ GB - L 11-5 (OVERALL), 1-1 (H2H), 5-1 (DIV), 10-4 (COMMON), 8-4 (CONF) Packers: SF - W @ Det - W NYG - L @ NE - W Chi - W 11-5 (OVERALL), 5-1 (DIV), 10-4 (COMMON), 8-4 (CONF) Then it would come down to strength of victory....so this is how that looks right now: Bears: 2-9 (DET) 3-8 (DAL) 7-4 (GB) 1-10 (CAR) 2-9 (BUF) 4-7 (MIN) 6-5 (MIA) 7-4 (PHI) ----------- 32-56 (TOTAL) Packers: 7-4 (PHI) 2-9 (BUF) 2-9 (DET) 4-7 (MIN) 9-2 (NYJ) 3-8 (DAL) 4-7 (MIN) ----------- 31-46 (TOTAL) Right now the difference in strength of victory is solely in the Bears extra victory over the Packers being over a 1-10 Carolina team. Otherwise, their other 7 victorys each even out (5 common victories, plus the Bears beating GB and Miami evens out over Minnesota (#2) and the Jets). Unfortunately the Packers don't have any 1-10 teams to beat. If the scenario that produces this tiebreaker being needed happens, the Packers would win this tiebreaker easily with the remaining teams they beat having a 26-28 record (factoring W/L to the Bears and Packers) and the Bears 15-22. Even if these teams won all remaining games not against the Bears and vice versa for the Packers, the Packers would still win the SOV tiebreaker.