This is not only strange logic, it's illogical logic. The best leadoff man for a team with bad OBP is a leadoff man with bad OBP? I'm arguing that when a team has bad OBP behind him, speed becomes the next important thing. Pierre creates runs with his speed. Let's take an extreme example of this. A player who is so slow he can only advance one base at a time has a 1.000 OBP. He walks every single time, so the team puts him at leadoff. The team behind him only has a .200 OBP, so they are only going to knock him in about 1 out of every 10 times. A player like Pierre with a .750 OBP only gets on 3 out of 4 times, but he only needs 1 hit to get him home, not 3. Therefore, the team knocks him home more often statistically then the player with the 1.000 OBP. Yes, this is absolutely absurd, but it works just as well with actual team numbers. A player with a .400 OBP is wasted if the team behind them can not string together hits to get them home, and so a player like Pierre with a .330 OBP is actually statistically more likely to get home with one hit from the hitters behind him with his speed. The best scenario is to get a lineup who has great OBP hitters, but for this team Juan Pierre has the best statistical chance of scoring per at bat. First off, if the guy is so slow he can only advance 1 base at a time, 1 out of 10 times he'll only get to 2nd base. Anywho, you're neglecting the failure rates of subsequent batters. A "hit" to drive him in is only going to happen 3 out of 10 times with a good hitter behind him. Keep in mind, too, that Pierre does not steal a base with each single/walk/HBP (132 singles/BB/HBP, 32 SBs), so more often than not it will take more than just 1 hit to get him in. Now you're counting on having 2 good hitters behind him for him to score when he gets on base, which is going to happen more often with a leadoff hitter who gets on base more often.